Alcohol
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Alcoholic beverages
•Beer
– 10° = 4 vol. % (3.16 g v 0.1 l = 15.8 g v 0,5 l)
– 12° = 5 vol. % (3.95 g v 0.1 l = 19.7 g v 0,5 l)
•Wine – cca 11% (7.9 g v 0.1 l = 15.8 g v 0.2 l)
•Spirits – 40 % (31.6 g v 0.1 l = 15.8 g v 0,05 l)

t
‰=millesimal
Blood-alcohol concentration (BAC)
I.
II.
Absorption
Elimination
Peak

Absorption
•Fullness and content of the stomach
•CO2 content
•Concentration
•Temperature

Metabolism of ethanol
•ADH (alcoholdehydrogenase)
•MEOS (microsomal ethanol oxidation system)
•Catalase

1.Alcohol
2.Acetaldehyde
3.CO2 and water

Velocity of elimination
•0.12 – 0.20 g/kg per hour


Analysis of alcohol
1.Specific gas chromatography – physical method
2.Non-specific Widmark´s proof – chemical method

Calculation
1.Backward calculation
2.Balance calculation

Backward calculation
peak
t
‰
Criminal act
Sample
0,12 – 0,20 ‰ /hour

   Alcohol (g) – absorption deficit
BAC ‰=
   Weight (kg) x reduction factor
Balance calculation (formula)
absorption deficit = 10%
reduction factor:♀= 0.6
♂= 0.7

Example
•Man (weight 70 kg) drank from 7.00 p.m. till 9.00 p.m. five snifters „shots“ (0.05 l) of vodka (40
vol. %).
•? BAC at 11.00 p.m. ?
•

Example - result
•
•        79 – 7.9
•Ct = ——————  – 0.20 x 4 = 0.65
•          70 x 0.7
•
•         79 – 7.9
•Ct = ——————  – 0.12 x 4 = 0.97
•          70 x 0.7
•
•Ct = 0.65 – 0,97 g/kg